# C语言经典算法100例（一）

By [Untitled](https://paragraph.com/@0xe92c9d75d40b93c5b6b6267e21118e3844788478) · 2021-11-14

---

include <stdio.h>
=================

include <stdlib.h>
==================

void main() { double l, r;

    scanf_s("%lf", &l);
    
    l = l / 10000;
    
    if (l <= 0.0) {
        printf("Please input the right profit!");
    }
    else if(l > 0.0 & l <= 10.0){
        r = l * 0.1;
    }
    else if (l > 10.0 & l <= 20.0) {
        r = 10 * 0.1 + (l - 10) * 0.075;
    }
    else if (l > 20.0 & l <= 40.0) {
        r = 10 * 0.1 + 10 * 0.075 + (l - 20) * 0.05;
    }
    else if(l > 40.0 & l <= 60.0){
        r = 10 * 0.1 + 10 * 0.075 + 20 * 0.05 + (l - 40) * 0.03;
    }
    else if (l > 60.0 & l <= 100.0) {
        r = 10 * 0.1 + 10 * 0.075 + 20 * 0.05 + 40 * 0.03 + (l - 60) * 0.015;
    }
    else {
        r = 10 * 0.1 + 10 * 0.075 + 20 * 0.05 + 40 * 0.03 + 40 * 0.015 + (l - 100) * 0.01;
    }
    
    printf("Your reward is %.2f", r * 10000);
    
    system("pause");
    return;
    

} ———————————————— 版权声明：本文为CSDN博主「来一斤小龙虾」的原创文章，遵循CC 4.0 BY-SA版权协议，转载请附上原文出处链接及本声明。 原文链接：[https://blog.csdn.net/lxh1002/article/details/81031510](https://blog.csdn.net/lxh1002/article/details/81031510)

---

*Originally published on [Untitled](https://paragraph.com/@0xe92c9d75d40b93c5b6b6267e21118e3844788478/c-100)*