# 随机钱包私钥源码

By [punk2898 🙌💎](https://paragraph.com/@2898punk) · 2023-04-17

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当然上述的玩法仅供娱乐

假设你的算力水平每秒 900 万个比特币地址

即每秒约 2^23 个比特币地址

暴力破解需要花掉的时间就是

2^（160-23） = 2^137 秒！

换算之后超过 1024 年！

    import random
    from web3 import Web3
    from mnemonic import Mnemonic
    
    # 使用BIP39单词列表
    mnemo = Mnemonic("english")
    
    # 使用Web3连接以太坊网络
    w3 = Web3(Web3.HTTPProvider('https://mainnet.infura.io/v3/xxxx'))
    
    # 设置一个助记词变量和一个余额变量
    seed_phrase = ""
    balance = 0
    
    # 当余额为0时，持续生成助记词并检查余额
    while balance == 0:
        # 随机生成一个12个单词的助记词
        # seed_phrase = mnemo.generate(128)
        seed_phrase = mnemo.generate(strength=256)
    
        
        # 将助记词转换为私钥
        private_key = mnemo.to_entropy(seed_phrase)
        
        # 将私钥转换为地址
        address = w3.to_checksum_address(w3.eth.account.from_key(private_key).address)
        
        # 检查余额
        # balance = w3.eth.getBalance(address)
        balance = w3.eth.get_balance(address)
    
        
        # 打印地址和余额
        print("Address:", address, "Balance:", w3.from_wei(balance, 'ether'))
        
    # 如果找到了余额，则打印助记词
    print("Seed phrase:", seed_phrase)

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*Originally published on [punk2898 🙌💎](https://paragraph.com/@2898punk/dlELSr7Pg5MVIaM7sit2)*