# APX交易挖矿简易分析 **Published by:** [CryptoWuhoo](https://paragraph.com/@cryptowuhoo/) **Published on:** 2021-12-27 **URL:** https://paragraph.com/@cryptowuhoo/apx ## Content APX上线首次交易挖矿活动: https://apollox.zendesk.com/hc/zh-cn/articles/4413129419161-ApolloX%E4%B8%8A%E7%BA%BF%E4%BA%A4%E6%98%93%E5%A5%96%E5%8A%B1%E6%B4%BB%E5%8A%A8-%E9%94%81%E4%BB%93%E5%8A%A0%E9%80%9F%E8%B5%9A%E5%8F%96APX%E5%A5%96%E5%8A%B1做一下规则的推导: 用户今日结束应获得APX奖励r=R*f*b/sum(w1-wk),假设APX价格为p(Price),则 r*p=R*f*b*p /sum(w1-wk) 如果要r*p大于交易成本f,则 f < R*f*b*p/sum(w1-wk) 即 R * b *p> sum(w1-wk) 结论 2000000* 倍数* APX价格 如果大于每日总分,则能回本,则存在套利空间 如果存在倍数需大于1时且在2.5内能套利,则会加大质押,买盘增加,币价上增,螺旋上升 如果倍数2.5也不能套利,则没有质押和交易动力,卖盘增加,币价下跌 以上结论仅作为操作参考。具体变化我这几天会继续跟踪,欢迎关注我的推特。个人推特:关注项目价值 研究 https://twitter.com/cryptowuhoo ## Publication Information - [CryptoWuhoo](https://paragraph.com/@cryptowuhoo/): Publication homepage - [All Posts](https://paragraph.com/@cryptowuhoo/): More posts from this publication - [RSS Feed](https://api.paragraph.com/blogs/rss/@cryptowuhoo): Subscribe to updates