# 基于python的sunflower 简易收菜脚本

**Published by:** [qingyun.eth](https://paragraph.com/@qingyun/)
**Published on:** 2022-04-10
**URL:** https://paragraph.com/@qingyun/python-sunflower

## Content

sunflower 网页小游戏 简介主要是向日葵1分钟一次收菜 比较繁琐 所以使用python的pyautogui自动化脚本 结合屏幕取点工具，定出点击坐标 半小时即可完成收菜、领reward脚本 缺陷是没做过检测解决思路1.自动化收菜出生地，5个格子 第二块地，5个格子 拿到其中一块的坐标，其余自动连带即可2.有几率弹出的rewardreward需要点击一次箱子 箱子属于随机出现在对话框 使用识图查坐标的函数定位到箱子 再点击代码import pyautogui import time # 默认这项功能为True, 这项功能意味着：当鼠标的指针在屏幕的最坐上方，程序会报错；目的是为了防止程序无法停止 pyautogui.FAILSAFE = False # 意味着所有pyautogui的指令都要暂停一秒；其他指令不会停顿；这样做，可以防止键盘鼠标操作太快； pyautogui.PAUSE = 0.2 def corp(top_one_x, top_one_y): pyautogui.doubleClick(top_one_x,top_one_y) pyautogui.doubleClick(top_one_x + 85 ,top_one_y) pyautogui.doubleClick(top_one_x + 42 ,top_one_y + 45) pyautogui.doubleClick(top_one_x,top_one_y + 100) pyautogui.doubleClick(top_one_x + 85,top_one_y + 100) box() def box(): box_location = pyautogui.locateOnScreen('箱子.png') print(box_location) if box_location != None: x,y = pyautogui.center(box_location) pyautogui.click(x,y) time.sleep(3) box_location = pyautogui.locateOnScreen('箱子2.png') print(box_location) if box_location != None: x,y = pyautogui.center(box_location) pyautogui.click(x,y) time.sleep(3) box_location = pyautogui.locateOnScreen('close按钮.png') print(box_location) if box_location != None: x,y = pyautogui.center(box_location) pyautogui.click(x,y) time.sleep(3) if __name__ == '__main__': print(pyautogui.size()) # 返回所用显示器的分辨率； 输出：Size(width=1920, height=1080) width,height = pyautogui.size() print(width,height) top_one_x = 1005 top_one_y = 357 field_2_x = 495 field_2_y = 676 #运行次数 count = 2 for i in range(1,count +1): print('次数：') print(i) for j in range(0,2): corp(top_one_x, top_one_y) corp(field_2_x, field_2_y) corp(top_one_x, top_one_y) corp(field_2_x, field_2_y) pyautogui.moveTo(1055,0,duration=1) time.sleep(3) for j in range(0,2): corp(top_one_x, top_one_y) corp(field_2_x, field_2_y) corp(top_one_x, top_one_y) corp(field_2_x, field_2_y)

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