# AES Encrypt

**Published by:** [sddcg](https://paragraph.com/@sddcg/)
**Published on:** 2021-10-27
**URL:** https://paragraph.com/@sddcg/aes-encrypt

## Content

问题背景工作中，在和其他服务供应商对接时，有时需要使用AES加密方式实现接口的联调。算法逻辑需要自己实现，现把流程整理如下: 另，基于这篇文章 使用 PyCrypto 进行 AES/ECB/PKCS#5(7) 加密，PKC7填充方式等同于PKC5填充方式。安装依赖pip3 install crypto代码实现包括完整的代码及注解import base64 from Crypto.Cipher import AES class AESCipher: def __init__(self, key): self.key = key[0:16] #只截取16位 self.iv = "\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0" # 16位字符，用来填充缺失内容，可固定值也可随机字符串，具体选择看需求。 def __pad(self, text): """填充方式，加密内容必须为16字节的倍数，若不足则使用self.iv进行填充""" text_length = len(text) amount_to_pad = AES.block_size - (text_length % AES.block_size) if amount_to_pad == 0: amount_to_pad = AES.block_size pad = chr(amount_to_pad) return text + pad * amount_to_pad def __unpad(self, text): pad = ord(text[-1]) return text[:-pad] def encrypt(self, raw): """加密""" raw = self.__pad(raw) cipher = AES.new(self.key, AES.MODE_CBC, self.iv) return base64.b64encode(cipher.encrypt(raw)) def decrypt(self, enc): """解密""" enc = base64.b64decode(enc) cipher = AES.new(self.key, AES.MODE_CBC, self.iv ) return self.__unpad(cipher.decrypt(enc).decode("utf-8")) if __name__ == '__main__': e = AESCipher('8ymWLWJzYA1MvLF8') secret_data = "6860795567181583<REQDATA></REQDATA>242BB99CE386F2B1EA19CCCF606D20E2" enc_str = e.encrypt(secret_data) print('enc_str: ' + enc_str.decode()) dec_str = e.decrypt(enc_str) print('dec str: ' + dec_str) 输出: >>> enc_str: gO80A2YMTzkYTzSe6MDjwYLq2X3Du6WXP5CEj1qdaX7b39Egp1Dxj+CGs+PqWkuRkKhPNTt8BPQZfRpi4zj+1UxXjYkO51sRLwgARTlZDKY= >>> dec str: 6860795567181583<REQDATA></REQDATA>242BB99CE386F2B1EA19CCCF606D20E2

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